0=-16x^2+70x+5

Solution for 0=-16x^2+70x+5 equation:

0=-16x^2+70x+5

We move all terms to the left:

0-(-16x^2+70x+5)=0

We add all the numbers together, and all the variables

-(-16x^2+70x+5)=0

We get rid of parentheses

16x^2-70x-5=0

a = 16; b = -70; c = -5;
Δ = b2-4ac
Δ = -702-4·16·(-5)
Δ = 5220
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{5220}=\sqrt{36*145}=\sqrt{36}*\sqrt{145}=6\sqrt{145}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-70)-6\sqrt{145}}{2*16}=\frac{70-6\sqrt{145}}{32}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-70)+6\sqrt{145}}{2*16}=\frac{70+6\sqrt{145}}{32}
$